Re: computing z-scores

On 05/24/2018 10:15 AM, Martin Mueller wrote:
> You construct a z-score for a set of values by subtracting the average from the value and dividing the result by the standard deviation. I know how to do this in a two-step procedure. First, I compute the average and standard deviation. In a second run I use the formula and apply it to each value.
>
> Is there a way of doing this in a single-step procedure or can you chain the two parts together in one query?  This goes beyond my SQL competence.

What about this?

SELECT value, (value - AVG(value))/stddev(value) as zvalue
FROM sometable
WHERE some conditions
GROUP by value


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