Re: [PATCH] GROUP BY ALL
Isaac Morland <isaac.morland@gmail.com>
From: Isaac Morland <isaac.morland@gmail.com>
To: "David G. Johnston" <david.g.johnston@gmail.com>
Cc: David Christensen <david@pgguru.net>,
pgsql-hackers <pgsql-hackers@postgresql.org>
Date: 2024-07-22T21:40:55Z
Lists: pgsql-hackers
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API reference →
-
Add GROUP BY ALL.
- ef38a4d9756d 19 (unreleased) landed
-
Refactor to avoid code duplication in transformPLAssignStmt.
- b0fb2c6aa5a4 19 (unreleased) landed
-
Fix missed copying of groupDistinct in transformPLAssignStmt.
- b7f6798c056a 16.11 landed
- 9ca79896aba3 15.15 landed
- 78a284b0b8d4 18.1 landed
- 7504d2be9eb4 19 (unreleased) landed
- 3fc9aa5b0233 17.7 landed
- 0be39b4b1a01 14.20 landed
On Mon, 22 Jul 2024 at 17:34, David G. Johnston <david.g.johnston@gmail.com>
wrote:
> On Mon, Jul 22, 2024 at 1:55 PM David Christensen <david@pgguru.net>
> wrote:
>
>> I see that there'd been some chatter but not a lot of discussion about
>> a GROUP BY ALL feature/functionality. There certainly is utility in
>> such a construct IMHO.
>>
>> Still need some docs; just throwing this out there and getting some
>> feedback.
>>
>>
> I strongly dislike adding this feature. I'd only consider supporting it
> if it was part of the SQL standard.
>
> Code is written once and read many times. This feature caters to
> the writer, not the reader. And furthermore usage of this is prone to be
> to the writer's detriment as well.
>
And for when this might be useful, the syntax for it already exists,
although a spurious error message is generated:
odyssey=> select (uw_term).*, count(*) from uw_term group by uw_term;
ERROR: column "uw_term.term_id" must appear in the GROUP BY clause or be
used in an aggregate function
LINE 1: select (uw_term).*, count(*) from uw_term group by uw_term;
^
I'm not sure exactly what's going on here — it's like it's still seeing the
table name in the field list as only a table name and not the value
corresponding to the whole table as a row value (But in general I'm not
happy with the system's ability to figure out that a column's value has
only one possibility given the grouping columns). You can work around:
odyssey=> with t as (select uw_term, count(*) from uw_term group by
uw_term) select (uw_term).*, count from t;
This query works.