Re: Making the subquery alias optional in the FROM clause

Zhihong Yu <zyu@yugabyte.com>

From: Zhihong Yu <zyu@yugabyte.com>
To: Dean Rasheed <dean.a.rasheed@gmail.com>
Cc: Tom Lane <tgl@sss.pgh.pa.us>, PostgreSQL Hackers <pgsql-hackers@lists.postgresql.org>
Date: 2022-07-09T13:53:30Z
Lists: pgsql-hackers
On Sat, Jul 9, 2022 at 5:18 AM Dean Rasheed <dean.a.rasheed@gmail.com>
wrote:

> On Sat, 9 Jul 2022 at 12:24, Zhihong Yu <zyu@yugabyte.com> wrote:
> >
> >  It seems the code would be more readable if you keep the assignment in
> else block below:
> >
> > +                   else if (rte->rtekind == RTE_SUBQUERY ||
> > +                            rte->rtekind == RTE_VALUES)
> >                         continue;
> > -                   rtename = rte->join_using_alias->aliasname;
> >                 }
> > -               else
> > -                   rtename = rte->eref->aliasname;
> >
> > because rtename would be assigned in the `rte->rtekind == RTE_JOIN` case.
> >
>
> But then it would need 2 else blocks, one inside the rte->alias ==
> NULL block, for when rtekind is not RTE_JOIN, RTE_SUBQUERY or
> RTE_VALUES, and another after the block, for when rte->alias != NULL.
> I find it more readable this way.
>
> Regards,
> Dean
>

Hi, Dean:
Thanks for the explanation.

I should have looked closer :-)

Commits

  1. Make subquery aliases optional in the FROM clause.