Thread
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Need help with a special JOIN
Andreas <maps.on@gmx.net> — 2012-09-29T16:02:23Z
Hi, asume I've got 2 tables objects ( id int, name text ) attributes ( object_id int, value int ) attributes has a default entry with object_id = 0 and some other where another value should be used. e.g. objects ( 1, 'A' ), ( 2, 'B' ), ( 3, 'C' ) attributes ( 0, 42 ), ( 2, 99 ) The result of the join should look like this: object_id, name, value 1, 'A', 42 2, 'B', 99 3, 'C', 42 I could figure something out with 2 JOINs, UNION and some DISTINCT ON but this would make my real query rather chunky. :( Is there an elegant way to get this?
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Re: Need help with a special JOIN
Samuel Gendler <sgendler@ideasculptor.com> — 2012-09-29T17:32:09Z
On Sat, Sep 29, 2012 at 9:02 AM, Andreas <maps.on@gmx.net> wrote: > Hi, > > asume I've got 2 tables > > objects ( id int, name text ) > attributes ( object_id int, value int ) > > attributes has a default entry with object_id = 0 and some other where > another value should be used. > > e.g. > objects > ( 1, 'A' ), > ( 2, 'B' ), > ( 3, 'C' ) > > attributes > ( 0, 42 ), > ( 2, 99 ) > > The result of the join should look like this: > > object_id, name, value > 1, 'A', 42 > 2, 'B', 99 > 3, 'C', 42 > > > I could figure something out with 2 JOINs, UNION and some DISTINCT ON but > this would make my real query rather chunky. :( > > Is there an elegant way to get this? > > I'm not sure it is any more elegant than the kind of solution you suggest, but this works: # select id, name, value from (select *, count(o.id) over (partition by o.id) as total from objects o join attributes a on a.object_id = o.id or a.object_id = 0) q where total = 1 or object_id != 0; id | name | value ----+------+------- 1 | A | 42 2 | B | 99 3 | C | 42
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Re: Need help with a special JOIN
David Johnston <polobo@yahoo.com> — 2012-09-29T17:33:56Z
On Sep 29, 2012, at 12:02, Andreas <maps.on@gmx.net> wrote: > Hi, > > asume I've got 2 tables > > objects ( id int, name text ) > attributes ( object_id int, value int ) > > attributes has a default entry with object_id = 0 and some other where another value should be used. > > e.g. > objects > ( 1, 'A' ), > ( 2, 'B' ), > ( 3, 'C' ) > > attributes > ( 0, 42 ), > ( 2, 99 ) > > The result of the join should look like this: > > object_id, name, value > 1, 'A', 42 > 2, 'B', 99 > 3, 'C', 42 > > > I could figure something out with 2 JOINs, UNION and some DISTINCT ON but this would make my real query rather chunky. :( > > Is there an elegant way to get this? > General form (idea only, syntax not tested) Select objectid, name, coalesce(actuals.value, defaults.value) From objects cross join (select ... From attributes ...) as defaults Left join attributes as actuals on ... Build up a master relation with all defaults then left join that against the attributes taking the matches where present otherwise taking the default. David J.
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Re: Need help with a special JOIN
Victor Sterpu <victor@caido.ro> — 2012-09-29T18:28:45Z
This is a way to do it, but things will change if you have many attributes/object SELECT o.*, COALESCE(a1.value, a2.value) FROM objects AS o LEFT JOIN attributes AS a1 ON (a1.object_id = o.id) LEFT JOIN attributes AS a2 ON (a2.object_id = 0); On 29.09.2012 19:02, Andreas wrote: > Hi, > > asume I've got 2 tables > > objects ( id int, name text ) > attributes ( object_id int, value int ) > > attributes has a default entry with object_id = 0 and some other > where another value should be used. > > e.g. > objects > ( 1, 'A' ), > ( 2, 'B' ), > ( 3, 'C' ) > > attributes > ( 0, 42 ), > ( 2, 99 ) > > The result of the join should look like this: > > object_id, name, value > 1, 'A', 42 > 2, 'B', 99 > 3, 'C', 42 > > > I could figure something out with 2 JOINs, UNION and some DISTINCT ON > but this would make my real query rather chunky. :( > > Is there an elegant way to get this? > >
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Re: Need help with a special JOIN
Johnny Winn <j.winn.v@gmail.com> — 2012-09-29T19:11:33Z
On Sat, Sep 29, 2012 at 2:28 PM, Victor Sterpu <victor@caido.ro> wrote: > This is a way to do it, but things will change if you have many > attributes/object > > SELECT o.*, COALESCE(a1.value, a2.value) > FROM objects AS o > LEFT JOIN attributes AS a1 ON (a1.object_id = o.id) > LEFT JOIN attributes AS a2 ON (a2.object_id = 0); > > On 29.09.2012 19:02, Andreas wrote: > >> Hi, >> >> asume I've got 2 tables >> >> objects ( id int, name text ) >> attributes ( object_id int, value int ) >> >> attributes has a default entry with object_id = 0 and some other where >> another value should be used. >> >> e.g. >> objects >> ( 1, 'A' ), >> ( 2, 'B' ), >> ( 3, 'C' ) >> >> attributes >> ( 0, 42 ), >> ( 2, 99 ) >> >> The result of the join should look like this: >> >> object_id, name, value >> 1, 'A', 42 >> 2, 'B', 99 >> 3, 'C', 42 >> >> >> I could figure something out with 2 JOINs, UNION and some DISTINCT ON but >> this would make my real query rather chunky. :( >> >> Is there an elegant way to get this? >> >> >> > > > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/**mailpref/pgsql-sql<http://www.postgresql.org/mailpref/pgsql-sql> > I like this join option because it's a little more simplified. Depending on the "default option" requirement you could change the nested select or otherwise replace all together. SELECT "Objects"."ID", "Objects"."Name", COALESCE("Attributes".value, (SELECT "Attributes".value FROM "Attributes" WHERE object_id = 0)) FROM "Objects" LEFT JOIN "Attributes" ON "Objects"."ID" = "Attributes".object_id; Thanks, Johnny