Re: Support logical replication of DDLs

Zheng Li <zhengli10@gmail.com>

From: Zheng Li <zhengli10@gmail.com>
To: Amit Kapila <amit.kapila16@gmail.com>
Cc: Japin Li <japinli@hotmail.com>, Alvaro Herrera <alvherre@alvh.no-ip.org>, Dilip Kumar <dilipbalaut@gmail.com>, rajesh singarapu <rajesh.rs0541@gmail.com>, PostgreSQL Hackers <pgsql-hackers@lists.postgresql.org>
Date: 2022-05-13T21:01:33Z
Lists: pgsql-hackers

Commits

Same data as JSON: GET /api/v1/messages/:b64id/commits the thread's linked commits as JSON, with link sources. API reference →
  1. Add a run_as_owner option to subscriptions.

  2. Refactor pgoutput_change().

  3. Print the correct aliases for DML target tables in ruleutils.

  4. Fix object identity string for transforms

  5. Add grantable MAINTAIN privilege and pg_maintain role.

  6. Get rid of recursion-marker values in enum AlterTableType

  7. Release cache tuple when no longer needed

  8. Empty search_path in logical replication apply worker and walsender.

  9. Refactor format_type APIs to be more modular

  10. Use wrappers of PG_DETOAST_DATUM_PACKED() more.

Attachments

> > 4. The handling related to partition tables seems missing because, on
> > the subscriber-side, it always creates a relation entry in
> > pg_subscription_rel which won't work. Check its interaction with
> > publish_via_partition_root.
>
> I will test it out.

Hi,

patch 0010 properly handles partitioned table creation on the apply
worker. Whether a replicated partitioned table should be added to
pg_subscription_rel catalog depends on the setting of
publish_via_partition_root of the publication. Thus we need to connect
to the source DB and check if the partitioned table is in
pg_catalog.pg_publication_tables after the apply worker creates the
partitioned table.

Thanks to Borui Yang for enabling and testing replication of DDL type
T_RenameStmt in patch 0009.

I've also rebased all the patches. Github branch of the same change
can be found here:
https://github.com/zli236/postgres/commits/ddl_replication

Regards,
Zheng