RE: DATE_PART() BUG? We have an SQL statement that is giving wro ng output.

Thanks!  That did it:

tbs=# SELECT DATE_PART('DAY', CAST('04/1/2001' AS DATE)) as dayofmonth;
 dayofmonth 
------------
         31
(1 row)

tbs=# SET TIMEZONE = 'GMT' ;
SET VARIABLE
tbs=# SELECT DATE_PART('DAY', CAST('04/1/2001' AS DATE)) as dayofmonth;
 dayofmonth 
------------
          1
(1 row)

Thanks for the quick response.

> -----Original Message-----
> From: Thomas Lockhart [mailto:lockhart@fourpalms.org]
> Sent: Friday, May 25, 2001 9:45 AM
> To: pkelly@ets.net; pgsql-bugs@postgresql.org
> Subject: Re: DATE_PART() BUG? We have an SQL statement that is giving
> wrong output.
> 
> 
> > Short Description
> > DATE_PART() BUG?  We have an SQL statement that is giving 
> wrong output.
> > tbs=# SELECT version();
> > -------------------------------------------------------------
> >  PostgreSQL 7.0.2 on i686-pc-linux-gnu, compiled by gcc 2.96
> > Here is a simple example:
> > SELECT DATE_PART('DAY', CAST('04/1/2001' AS DATE)) as dayofmonth
> > ----------
> >          31
> > Why does April 1st display as May 31st?
> 
> This is a known "feature" of 7.0.x (and earlier) on daylight savings
> time boundaries. You will see the problem go away if you set your time
> zone to GMT. Upgrade to 7.1.x.
> 
>                     - Thomas
>