Re: Schema variables - new implementation for Postgres 15
Julien Rouhaud <rjuju123@gmail.com>
From: Julien Rouhaud <rjuju123@gmail.com>
To: Pavel Stehule <pavel.stehule@gmail.com>
Cc: Dean Rasheed <dean.a.rasheed@gmail.com>, Joel Jacobson <joel@compiler.org>, PostgreSQL Hackers <pgsql-hackers@lists.postgresql.org>
Date: 2022-01-25T08:48:21Z
Lists: pgsql-hackers
Commits
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API reference →
-
Allow underscores in integer and numeric constants.
- faff8f8e47f1 16.0 cited
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Remove special outfuncs/readfuncs handling of RangeVar.catalogname.
- 3cece34be842 16.0 cited
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Remove extra space from dumped ALTER DEFAULT PRIVILEGES.
- 2af33369e794 16.0 cited
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Create FKs properly when attaching table as partition
- b0284bfb1db5 16.0 cited
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psql: improve tab-complete's handling of variant SQL names.
- 02b8048ba5dc 15.0 cited
Hi,
On Tue, Jan 25, 2022 at 09:35:09AM +0100, Pavel Stehule wrote:
> út 25. 1. 2022 v 6:18 odesílatel Julien Rouhaud <rjuju123@gmail.com> napsal:
>
> > I think the lock should be
> > acquired during IdentifyVariable. It should probably be optional as one
> > codepath only needs the information to raise a warning when a variable is
> > shadowed, so a concurrent drop isn't a problem there.
> >
>
> There is a problem, because before the IdentifyVariable call I don't know
> if the variable will be shadowed or not.
>
> If I lock a variable inside IdentifyVariable, then I need to remember if I
> did lock there, or if the variable was locked already, and If the variable
> is shadowed and if lock is fresh, then I can unlock the variable.
But in transformColumnRef() you already know if you found a matching column or
not when calling IdentifyVariable(), so you know if an existing variable will
shadow it right?
Couldn't you call something like
lockit = node == NULL;
varid = IdentifyVariable(cref->fields, &attrname, ¬_unique, lockit);
The only other caller is transformLetStmt(), which should always lock the
variable anyway.