Re: BUG #15587: Partitions with ALTER TABLE ADD CONSTRAINT
Alvaro Herrera <alvherre@2ndquadrant.com>
From: Alvaro Herrera <alvherre@2ndquadrant.com>
To: jesper.pedersen@redhat.com, pgsql-bugs@lists.postgresql.org
Date: 2019-01-10T17:11:23Z
Lists: pgsql-bugs
On 2019-Jan-10, PG Bug reporting form wrote: > The following works > > CREATE TABLE t1 (i1 INT NOT NULL, i2 INT NOT NULL) PARTITION BY HASH (i1); > > \o /dev/null > SELECT 'CREATE TABLE t1_p' || x::text || ' PARTITION OF t1 > FOR VALUES WITH (MODULUS 64, REMAINDER ' || x::text || ');' > from generate_series(0,63) x; > \gexec > \o > > ALTER TABLE ONLY t1 ADD CONSTRAINT uniq_t1_i1_i2 UNIQUE (i1, i2); > > which gives > > test=# \d+ t1 > Partitioned table "public.t1" > Column | Type | Collation | Nullable | Default | Storage | Stats target > | Description > --------+---------+-----------+----------+---------+---------+--------------+------------- > i1 | integer | | not null | | plain | > | > i2 | integer | | not null | | plain | > | > Partition key: HASH (i1) > Indexes: > "uniq_t1_i1_i2" UNIQUE CONSTRAINT, btree (i1, i2) INVALID > > > Removing ONLY from the ALTER command makes the index correct. I'm not clear what problem you're reporting. If you use ONLY, then the command doesn't cascade to create the index on partitions, and the index is marked invalid. If you add the constraint to each partition and ALTER INDEX ATTACH PARTITION, the index on t1 should become valid when every partition of the table has its index. -- Álvaro Herrera https://www.2ndQuadrant.com/ PostgreSQL Development, 24x7 Support, Remote DBA, Training & Services
Commits
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Fix creation of duplicate foreign keys on partitions
- 0325d7a5957b 12.0 landed
- 4dff8935fbab 11.2 landed