Re: [HACKERS] What is nameout() for?

> Actually, I have 'C' question regarding the above code. Where does the
> "-" live in RAM? Does the compiler generated a data hunk such that this
> string will be apart of the final executable and each invocation of this
> routine would result in a pointer to that 'global' location being
> returned? 
> Or does it allocate the memory for, and initialize, the "-" on the stack? 
> If so, isn't returning a "-" a dangerous act?
> 
> In fact, isn't returning a "-" dangerous either way without the 
> protoype being:

One copy, usually in the text segment because it is ready-only.


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