Re: select where id=random()*something returns two results

Rod Taylor <rbt@rbt.ca>

From: Rod Taylor <rbt@rbt.ca>
To: Ulrich Meis <u.meis@gmx.de>
Cc: pgsql-bugs@postgresql.org
Date: 2003-09-19T01:25:14Z
Lists: pgsql-bugs
> select * from quotes where id=1+round(random()* cast ((select max(id)
> from quotes) as double precision));
>  id  |                           quote                           |
> author      
> -----+-----------------------------------------------------------+------
> -----------
>  187 | Vergib Deinen Feinden, aber vergiss niemals ihre Namen.   | John
> F. Kennedy
>  377 | Die Wirklichkeit ist nicht so oder so, sondern so und so. | Harry
> Mulisch
> (2 rows)
> 
> I'm not really into databases, but this sounds wrong. Most of the time,
> I actually get 0 results.

Random is calculated per call (in this case per comparison). So, the
value you compare against for 187 is not the same as 377.

UPDATE table SET column = random(); will show the effect.

If you wrap randon() in a subselect, it will cause it to be evaluated
once:

SELECT * from quotes where id = 1+round((SELECT random()) * cast(....).



However, a much faster query for your purposes would be:

SELECT * FROM quotes ORDER BY random() LIMIT 1;