values_test.diff
text/x-patch
Filename: values_test.diff
Type: text/x-patch
Part: 0
Patch
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API reference →
Format: unified
| File | + | − |
|---|---|---|
| src/test/regress/expected/subselect.out | 8 | 20 |
| src/test/regress/sql/subselect.sql | 2 | 5 |
diff --git a/src/test/regress/expected/subselect.out b/src/test/regress/expected/subselect.out
index 288d139cfdd..33a10e8f518 100644
--- a/src/test/regress/expected/subselect.out
+++ b/src/test/regress/expected/subselect.out
@@ -2755,28 +2755,16 @@ SELECT * from onek WHERE unique1 in (VALUES(1200::bigint), (1));
-- VtA shouldn't depend on the side of the join probing with the VALUES expression.
EXPLAIN (COSTS OFF)
-SELECT c.oid,c.relname FROM pg_class c JOIN pg_am a USING (oid)
-WHERE a.oid IN (VALUES (1), (2));
- QUERY PLAN
----------------------------------------------------------
- Nested Loop
- -> Seq Scan on pg_am a
- Filter: (oid = ANY ('{1,2}'::oid[]))
- -> Index Scan using pg_class_oid_index on pg_class c
- Index Cond: (oid = a.oid)
-(5 rows)
-
-EXPLAIN (COSTS OFF)
-SELECT c.oid,c.relname FROM pg_class c JOIN pg_am a USING (oid)
-WHERE c.oid IN (VALUES (1), (2));
- QUERY PLAN
----------------------------------------------------------------
+SELECT c.unique1,c.ten FROM onek c JOIN tenk1 a USING (ten)
+WHERE a.ten IN (VALUES (1), (2));
+ QUERY PLAN
+--------------------------------------------------
Hash Join
- Hash Cond: (a.oid = c.oid)
- -> Seq Scan on pg_am a
+ Hash Cond: (a.ten = c.ten)
+ -> Seq Scan on tenk1 a
+ Filter: (ten = ANY ('{1,2}'::integer[]))
-> Hash
- -> Index Scan using pg_class_oid_index on pg_class c
- Index Cond: (oid = ANY ('{1,2}'::oid[]))
+ -> Seq Scan on onek c
(6 rows)
-- Constant expressions are simplified
diff --git a/src/test/regress/sql/subselect.sql b/src/test/regress/sql/subselect.sql
index 101167de810..46b12df9f5c 100644
--- a/src/test/regress/sql/subselect.sql
+++ b/src/test/regress/sql/subselect.sql
@@ -1243,11 +1243,8 @@ SELECT * from onek WHERE unique1 in (VALUES(1200::bigint), (1));
-- VtA shouldn't depend on the side of the join probing with the VALUES expression.
EXPLAIN (COSTS OFF)
-SELECT c.oid,c.relname FROM pg_class c JOIN pg_am a USING (oid)
-WHERE a.oid IN (VALUES (1), (2));
-EXPLAIN (COSTS OFF)
-SELECT c.oid,c.relname FROM pg_class c JOIN pg_am a USING (oid)
-WHERE c.oid IN (VALUES (1), (2));
+SELECT c.unique1,c.ten FROM onek c JOIN tenk1 a USING (ten)
+WHERE a.ten IN (VALUES (1), (2));
-- Constant expressions are simplified
EXPLAIN (COSTS OFF)